Question

An organic acid 'A' CH„0, reacts with Br, in presence of phosphorous to Compound 'B' contains an asymmetric carbon atom and yield 3-Methyl butan-2-enoic acid on dehydrobromination. Compound 'A' and 'B' respectively are:
a) 3-Methyl butanoic acid, 2- Bromo-3-methyl butanoic acid

b) 2-Methyl butanoic acid, 2- Bromo-3-methyl butanoic acid

c) 2-Methyl butanoic acid, 3- Bromo-3-methyl butanoic acid

d) 3-Methyl butanoic acid, 3- Bromo-3-methyl butanoic acid​

Answer 1

option D would be your ans

Answer 2

Answer:

Bromination will occur next to the COOH group as the COOH group make stable the carbocation

C does not show geometrical as the both groups on left side are same of double bond

Ozonolysis will break the bond and form secondary carbon to ketone and primary carbon to aldehyde

F( formaldehyde) does not give the Schiff base test.