An organic compound a(c3h8o) on treatment with copper at 573 k gives b, b does not reduce fehling's solution but gives a yellow . Of compound c with i2/naoh. Deduce the structure of a, b and
c.
Answers
Answered by
12
Answer:
The reaction scheme in the given question will be as follows:
1) As B gives negative fehling's test means B is not an aldehyde.
2) Copper at 573 K act as oxidising agent. Therefore, A is alcohol which gives ketone on oxidation.
3) This ketone gives positive iodoform test.
4) In positive iodoform test yellow precipitate of iodoform, CHI3 are obtained. "C" is iodoform.
Attachments:
Similar questions
English,
6 months ago
Chemistry,
6 months ago
English,
6 months ago
Computer Science,
11 months ago
Math,
11 months ago
Psychology,
1 year ago