An organic compound A , having the formula C3H8O, on treatment with copper at 573K gives B. B does not reduce Fehling’s solution but gives a yellow precipitate of the compound C with I2/NaOH. Deduce the structures of A,B and C. Also write the respective chemical reactions.
Answers
Answered by
9
A- ch3ch2ch20h B- ch3ch2cho and c-ch3c0ch3 propanol -----;-propanal propanal---; propanone Which give IODO FORM TEST
Answered by
9
Identification of compound A, B, and C
Given:
- Molecular formula of compound A =
- Compound 'A' on treatment with copper at 573K gives B.
- Compound 'B' on reaction with
yields Compound 'C'.
To find:
Compounds 'A', 'B' and 'C' = ?
Explanation:
- From the given molecular formula the compound 'A' is identified as secondary alcohol (Propanol).
- When the vapors of secondary alcohol is passed over heated copper at 573K, it leads to dehydrogenation and this yields a ketone called acetone.
- The chemical equation involved in the reaction is as follows:
.
- Thus from the above reaction, compound 'B' is identified as acetone or propanone.
- As acetone or propanone is a ketone, it does not reduces Fehling's solution.
- When acetone is made to react with
it leads to yellow color precipitate due to the formation of iodoform along with sodium acetate, sodium iodide and water as by product.
- The chemical equation involved in the reaction is as follows:
Conclusion:
From the above-given chemical equations compounds A', 'B' and 'C' are identified as follows:
- Compound A: Propanol
- Compound B: Propanone
- Compound C: Iodoform
Learn more about such concept
Identify the compound X on the basis of the reactions given below.
Also, write the name and chemical formulae of A, B and C.
+ Zn--> A + H2(g)
X + HCl ----> B + H2O
+ CH3COOH------------> C + H2O
brainly.in/question/2703105
(a) name the compounds ch3cooh and identify the functional group (b)give a chemical test to identify this compound (c) name the gas evolved when this compound acts on carbonate. hoe would you identify this gas
brainly.in/question/2453054
Similar questions