Chemistry, asked by DrAdieba, 9 months ago

An organic compound 'A' on treatment with HI gives 'B'. 'B' on treatment with ethanolic KOH gives 'C'
(an isomer of 'A'). Ozonolysis of 'C' (with Hl.0, work up) gives a two carbon carboxylic acid 'D' and a
four carbon ketone 'E'. Identify A,B,C,D and E.

Answers

Answered by harsharora111

3

Answer:

A = 3 methyl Pentane

B = 3 ido 3 methyl Pentane

C = 3 methyl Pent2 ene

D = Acetic Acid

E = Butane 2 one

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First Reaction is substitution

then E2, Ozonolysis ,

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Thanks for reading

Answered by wwwseenalingampalli

0

Explanation:

hope it is helpful to you

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