Question

An organic compound 'A' produces a gas with brisk effervescence when sodium bicarbonate is added to it. The compound 'A' contains same number of carbons as in ethane. The compound 'A' reacts with ethanol to form a sweet smelling compound 'C' in presence of conc. H2​SO4​ acid. Then the name of compound A and the gas evolved is :​

Answer 1

A contains the same number of carbon as in ethane. So number of carbon is 2.

A produces brisk effervescence when sodium bicarbonate is added to it. Therefore carbon dioxide is evolved. 

 CH3COOH+NaHCO3→CH3COONa+CO2+H2O

We know that esters are sweet smelling substances which are used in perfumes. These are formed when a carboxylic acid reacts with an alcohol in presence of conc. H2SO4. 

Since, new compound A (i.e., ethanoic acid) reacts with ethanol (an alcohol) in presence of conc. H2SO4 to form a sweet smelling substance which is used in perfumes, therefore C must be an ester, i.e., ethyl ethanoate.

  

CH3COOH+C2H5OH (Conc.H2SO4)----------->CH3COOCH2CH3+H2O

Option A is correct

Answer 2

Answer:

Compound A is ethanoic acid and gas liberated is CO2.

Explanation:

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