Question

An organic compound A upon reacting with NH₃ gives B.
On heating B gives C. C in presence of KOH reacts with Br₂
to given CH₃CH₂NH₂. A is :
(a) CH₃COOH (b) CH₃CH₂CH₂COOH
(c) CH₃ - CH - COOH
|
CH₃
(d) CH₃CH₂COOH

Answer 1

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(a) CH₃COOH

Answer 2

A is:

• An organic compound A upon reacting with NH₃ gives B. On heating B gives C. C in presence of KOH reacts with Br₂ to given CH₃CH₂NH₂.

• A + NH₃ → B + ∆ → C + Br₂ + KOH → CH₃CH₂NH₂

• We know that, C undergoes Hoffman bromamide reaction

• C must be Alkanamide.

• We get ethanamine as final product therefore C is propanamide.

• CH₃CH₂COOH +NH₃ → CH₃CH₂COO⁻ NH4⁺ → CH₃CH₂COO NH₂

• Hence, Compound 'A' is Propanoic acid CH₃ CH₂ CH₂ COOH