an organic compound c3h6o give positive tollen's test.identify the compound and write the reaction involved.
Answers
Answer:
1. An organic compound (A) reduces Tollen’s reagent it must be an aldehyde. From the formula, it is identified as CH3 – CH2 – CHO propanal. 2. Propanal on reaction with methyl magnesium bromide followed by acid hydrolysis gives (B) as Butan – 2 – ol. It must be a secondary alcohol and gives blue colour with victor meyer’s test. H 4. Wolf – Kishner reduction. Read more on Sarthaks.com - https://www.sarthaks.com/921055/organic-compound-molecular-formula-reduces-tollens-reagent-reaction-methyl-magnesium1. An organic compound (A) reduces Tollen’s reagent it must be an aldehyde. From the formula, it is identified as CH3 – CH2 – CHO propanal. 2. Propanal on reaction with methyl magnesium bromide followed by acid hydrolysis gives (B) as Butan – 2 – ol. It must be a secondary alcohol and gives blue colour with victor meyer’s test. H 4. Wolf – Kishner reduction. Read more on Sarthaks.com - https://www.sarthaks.com/921055/organic-compound-molecular-formula-reduces-tollens-reagent-reaction-methyl-magnesium
Explanation:
Answer:
Explanation:
The compound that gives positive Tollen's test is an aldehyde. The molecular formula of the organic compound c3h6o suggests that it can either be propanal (CH3CH2CHO) or acetone (CH3COCH3), but since it gives a positive Tollen's test, it can be concluded that it is propanal.
The Tollen's test is used to test the presence of aldehydes in a given organic compound. Here is the reaction involved:
Ag(NH3)2+ + e- → Ag + 2NH3
In the presence of an aldehyde, the Tollen's reagent (ammoniacal silver nitrate solution) is reduced to metallic silver, which forms a silver mirror on the walls of the test tube or flask.
The reaction for propanal can be written as:
CH3CH2CHO + 2Ag(NH3)2+ + 3OH- → CH3CHCH3CH2CHO + 2Ag(NH3)2+ + 3OH- → CH3CH