Question

. An organic compound chlorine, Hydrogen and Bromine. The percentage composition of Carbon is 12.8% and Hydrogen 2.1% 0.188g of the compound, on evaporation, displaced 22.4cm of dry air at S.T.P. Determine the molecular A formula of compound​

Answer 1

Answer:

Moles of C =

12

12.8

=1.067

Moles of H $=$\dfrac{2.1}{1.008}=2.08$$

Moles of Br =

79.9

85.1

=1.065

C=

1.065

1.067

=1, H=

1.065

2.08

=2, Br=

1.065

1.065

=1

Empirical formula =CH

2

Br

Molecular formula =(CH

2

Br)n

Empirical mass =93.9

Therefore n=

93.9

187.9

=2