Question

an organic compound contain 39.13% carbon 8.64% hydrogen remaining element is oxygen calculate the empirical and molecular for giving the vapour density of the compound is 92​

Answer 1

Answer:

Percentage oxygen = 100- ( 40+ 6.66)= 100 - 46.6 = 53.4%

Hence, empirical formula = CH

2

O

Now, empirical formula mass

=12+(2×1)+16=12+2+16=30

Molecular mass of given organic compound = vapor density x 2 = 30 x 2 = 60

n = Molecular mass / Empirical formula mass =

30

60

=2

Thus , Molecular formula = (Empirical formula)