Question

An organic compound contained 54.4% C and 9.13% H, determine the empirical formula and find the molecular formula of the vapour density is calculated as 24.

If u give silly silly answers then I will report u. So be cautious about this and answer.Thank you.

Answer 1

Molecular mass = vapour density × 2
= 24 ×2
= 48 amu


E.f
C = 54.4 ÷ 12 = 4.53
H = 9.13 ÷ 1. = 9.13
Oxygen = 36.4 ÷ 16 = 2.275

C = 4.53÷ 2.275 = 2
H = 9.31 ÷ 2.275 = 4
O = 2.275÷ 2.275 = 1


Hence e.f is c2h40

E.f mass = 44 amu

And molecular farmula will be c4h8o2

Hope it helps you. ..
Mark as brainlist plz PlzZ plz PlzZ plz

Answer 2

Answer is in the attachment.....

Hence the empirical formula is C2H4O.

Hope it helps......