an organic compound containing c and h gave the following analysis c=40% H=6.7%. it's empirical formula would be?
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I think your question is wrong correct question is
an organic compound containing c and h gave the following analysis c=40% H=6.7% and remaining is O . it's empirical formula would be?
so % of O(oxygen) = 100-(40+6.7) = 100-46.7 = 53.3 % .
Emperical formula :- It represent the simplest whole number ratio of atoms of the all the elements by number of moles.
molecular formula :- It represent the actual ratio of atoms of the all the elements by number of moles.
⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩
⏫Emperical formula :- CH2O.⏬
⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪
an organic compound containing c and h gave the following analysis c=40% H=6.7% and remaining is O . it's empirical formula would be?
so % of O(oxygen) = 100-(40+6.7) = 100-46.7 = 53.3 % .
Emperical formula :- It represent the simplest whole number ratio of atoms of the all the elements by number of moles.
molecular formula :- It represent the actual ratio of atoms of the all the elements by number of moles.
⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩⏩
⏫Emperical formula :- CH2O.⏬
⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪⏪
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bhawnaanand:
ya I also think that it's wrong question.
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I hope it will help you
please mark it as brainlist
please mark it as brainlist
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