Question

an organic compound containing c and H K the following analysis C = 40 % in H=6.7 % its empirical formula would be ​

Answer 1

c=H K

$\frac{40}{100} = \frac{6.7}{100} \times k$

$\frac{2}{5 } = 67 \times k \\ \frac{2}{5} \times 67 = k \\ \frac{2 \times 335}{5} = k \\ 2 \times 67 = k \\ 134 = k$