Question

An organic compound containing C, H and O gave on analysis
C – 40% and H – 6.66%. Its empirical formula would be
(a) C₃H₆O (b) CHO
(c) CH₂O (d) CH₄O

Answer 1

Answer: (D) CH2O

Explanation:

Answer 2

(c) CH₂O

Explanation:

At wt of C = 12

Rel Number for C = 40/12 = 3.22

Ratio for C = 3.66/3.33 = 1

At wt of H = 1

Rel Number for H = 6.66/1 = 6.66

Ratio for H = 6.66/3.33 = 2

At wt of O = 16

% of O = 100 – (40+6.66) = 53.34%

Rel Number for O = 53.34/16 = 3.33

Ratio for O = 3.33/3.33 = 1

Hence empirical formula is CH₂O