Question

An organic compound containing c.h.n.gave following analysis c=40%,h=13.33%

Answer 1

The question is incomplete though i know the whole question nitrogen=46.67%

atomic wt of C = 12

Relative C = 40/12 = 3.66

Ratio for C = 3.66/3.33 = 1.09

At wt of H = 1

Relative H = 13.33/1 = 13.33

Ratio for H = 13.33/3.33 = 4

At wt of N = 14

Relative N = 46.67/14 = 3.33

Ratio for N = 3.33/3.33 = 1

Hence empirical formula is CH₄N