Question

an organic compound contains 10.4% Karbonn 0.84 hydrogen and 89.1 2% chlorine find out empirical formula and molecular formula of molar mass of compound is 119.5 AMU​

Answer 1

Answer:

CHCl3

Explanation:

Find chorine’s percentage.

Cl= 100- (10.4+0.84) =100- 11.24= 88.76%

Find the mass of teach components in grams:

carbon: 10.4% so 10.4g out of 100g of total mixture.

hydrogen: 0.84g

Chlorine: 88.76g

find the no. of moles of each (no. of moles= total mass/ atomic mass):

Carbon: 10.4/ 12 = 0.8

hydrogen: 0.84/1 = 0.84

Chlorine: 88.76/35= 2.5

devide smallest mole vale by all mole values and write their ratio:

1:1:3 = C:H:Cl

Write the respective values of ratio as subscrits of the chemical symbol:

C1H1Cl3 = CHCl3  

SO CHCL3 IS THE EMPIRICAL FORMULA OF THE COMPOUND.

Find the empirical formula mass:

Mass of C + Mass of H + Mass of 3 atoms of Cl= empirical formula mass

12+1+(3x35)= 118 u

Divide the molecular mass (that is given in the question) with the empirical formula mass:

119.5/118 = 1.01 which is approximately 1

Multiply all the subscripts of the empirical formula with the answer of the previous step (which is 1 in this case):

C(1x1)H(1x1)CL(3x1)= CHCl3

Hence, the molecular formula of the compound is CHCl3