Question

An organic compound contains 40% carbon6.66% hydrogen and rest ofoxygen. If the vapor density ofthe compound is 30 then determine its molecular and empirical formulas.

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Answer 1

Answer:

Percentage of oxygen = 100 - (40 + 6.66) = 100 - 46.6 = 53.4% Element % Atomic mass Relative ratio of atoms Simplest ratio C 40 12 40/12 = 3.3 3.3/3.3 = 1 H 6.66 1.008 6.61/1.008 = 6.5 6.5/3.3 = 2 O 53.4 16 53.4/16 = 3.3 3.3/3.3 = 1 Hence, empirical formula = CH2O Now, empirical formula mass = 12 + (2 × 1) + 16 = 12 + 2 + 16 = 30″ Molecular mass = 2 x Vapour density = 2 × 30 = 60 n = Molecular mass / Empirical formula mass = \(\frac{60}{30}\) = 2 Thus, Molecular formula = (Empirical formula) × n = (CH2O) × 2 = C2H4O2Read more on Sarthaks.com - https://www.sarthaks.com/702859/in-organic-compound-40-carbon-66-hydrogen-and-rest-oxygen-present-its-vapour-destiny-is?show=702862#a702862

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Answer 2

Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.