An organic compound contains 53.33% by mass of C, 15.56% by mass of H and rest N. The empirical formula of the compound is
1) C2H6N
2) CH5N2
3)C2H5N
4)C2H7N
Answers
Answered by
0
HELLO FRIENDS
For this we make a table as:
Element
%Composition
Atomic Mass
Mole Ratio
Simple Ratio
C
40.00%
12
(40/12)
(3.33/3.33)=1
H
6.67%
1
(6.67/1)
(6.667/3.33)=2
O
53.33%
16
(53.33/16)
(3.33/3.33)=1
∴ Formula of compound is =CH
2
O
Answered by
0
Answer: a is correct option
Explanation:
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