Chemistry, asked by sharmatharini, 8 months ago

An organic compound contains 53.33% by mass of C, 15.56% by mass of H and rest N. The empirical formula of the compound is
1) C2H6N
2) CH5N2
3)C2H5N
4)C2H7N​

Answers

Answered by ratnasatvika
0

HELLO FRIENDS

For this we make a table as:

Element

%Composition

Atomic Mass

Mole Ratio

Simple Ratio

C

40.00%

12

(40/12)

(3.33/3.33)=1

H

6.67%

1

(6.67/1)

(6.667/3.33)=2

O

53.33%

16

(53.33/16)

(3.33/3.33)=1

∴ Formula of compound is =CH  

2

​  

O

Answered by Anonymous
0

Answer: a is correct option

Explanation:

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