Question

an organic compound contains 6*10^23 c atoms , 1.8 *10^24 h atoms and 3*10^23 o atoms the simplest formula of the compound will be​

Answer 1

Explanation:

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Answer 2

Given:

An organic compound contains 6*10^23 c atoms, 1.8 *10^24 h atoms and 3*10^23 o atoms.

To Find:

The simplest formula of the compound.

Solution:

To find the simplest formula for the compound will bewe will follow the following steps:

As we know,

The simplest ratio of an organic compound means its empirical formula.

So, first, we will calculate the number of moles of carbon, hydrogen and oxygen and then divide it to get the simplest ratio.

The molecular mass of carbon, hydrogen and oxygen is 12,1 and 16 respectively.

Also, 1 mole of a substance contains 6.022× 10²³ molecules or atoms. so, the number of moles can be calculated by the formula:

$number \: of \: moles = \frac{given \: atoms}{atoms \: in \: 1mole}$

$Number of moles \: of \: carbon = \frac{6.10 \times {10}^{23} }{6.022 \times {10}^{23} } = 1.0$

$Number of moles \: of \: hydrogen = \frac{1.8 \times {10}^{24} }{6.022 \times {10}^{23} } = 3.0$

$Number of moles \: of \: oxygen = \frac{3 \times {10}^{23} }{6.022 \times {10}^{23} } = 0.5$

Mole ration of carbon, hydrogen and oxygen = 1:3:1/2.

Now, multiplying by 2 all the three we get the simplest ratio which is 2:6:1

The simplest formula of the compound is C2H6O1.

Henceforth, the simplest formula of the compound will be C2H6O1.