Question

An organic Compound Contains 61% carbon 11.88% hydrogen and remaining
oxygen. Iſ vapour density of the compound be 59 then calculate its empirical
and molecular formula?
(1)​

Answer 1

Explanation:

C=61/12=5.08

H=11.8/1=11.8

O=27/16=1.68

Lowest ratio value multiple to all value

C=5.08/1.68=3.02

H=11.8/1.68=7.2

O=1.68/1.68=1.68

Empirical formula is =C3H7O1

Empirical formula mass =3×12+7×1+1×16=59

n=density /emyrical formula mass =59/59=1

Molecular formula =n×emyrical formula =1×C3H7O1=C3H7O

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Answer 2

Explanation:

c 2

k 3

Yes

3x2 6

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