Question

an organic compound contains 61%, h=11.8% and o=27.12% calucalate the empirical formula, if its molecular mass is 118 please answer the question pls​

Answer 1

Answer:

an organic compound contains 61%, h=11.8% and o=27.12% calucalate the empirical formula, if its molecular mass is 118 please answer the qquestion

your answer is below

Dear friend

C=61/12=5.08

H=11.8/1=11.8

O=27/16=1.68

Lowest ratio value multiple to all value

C=5.08/1.68=3.02

H=11.8/1.68=7.2

O=1.68/1.68=1.68

Empirical formula is =C3H7O1

Empirical formula mass =3×12+7×1+1×16=59

n=density /emyrical formula mass =59/59=1

Molecular formula =n×emyrical formula =1×C3H7O1=C3H7O

Answer 2

Explanation:

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