Question

An organic compound contains C = 21.56%, H = 4.56% and Br = 73.36%
Its molecular mass is 109 (atomic mass of Br = 80). Its molecular formula is
CAH, Br
COH Br
O
C,H, Br
C,H,Br​

Answer 1

Here's you answer

Divide all the percentage by the molar mass of the element each

$\frac{21.56}{12}$ = 1.8 Approx

$\frac{4.56}{1}$ = 4.56

$\frac{73.36}{80}$ = 0.9

Now, taking the simplest ratio,

18 : 45 : 9

2 : 5 : 1

= 2 carbon atoms, 5 hydrogen atoms , 1 bromine atom

Now, the compound will be:

C₂H₅Br

The molecular mass is: 12 x 2 + 1 x 5  + 80 x 1

= 24 + 5 + 80 = 109

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