an organic compound contains c =54.3% h= 9%. the molecular mass of the compound is 88u. what is molecular formula
Answers
C₂H₄O is ths compound
Step - by - step Explanation: C = 54.3%, H = 9% then O = 100% - (54.3 + 9)% = 36.7%.
Molecular Mass = 88 u
→ Carbon = 54.3/100 × 88u = 47.784
→ Hydrogen = 9/100 × 88u = 7.92
→ Oxygen = 36.7/100 × 88u = 32.296
Moles of
→ Carbon = 47.784/12 = 3.982 or 4
→ Hydrogen = 7.92/1 = 7.92 or 8
→ Oxygen = 32.296/16 = 2.0185 or 2
Molecular Formula
→ 3.982:7.92:2.0185 or 4:8:2
→ 2:4:1
Hence Compound is C₂H₄O
Question :
The molar mass of a compound is 88 g/mol. It contains 54.53% carbon, 9.15% hydrogen and 36.32% oxygen. What is the molecular formula of the compound?
Answer :
♣ In this case, a molar mass of 88g mol ⁻¹ tells you that one mole of this compound has a mass of 88 g
You can convert between percentages and grams by using a sample of
100 g.
Then we have :
→ Use the molar mass of each element to determine how many moles of each are present in one mole of this compound
We can say that one molecule of the compound will contain
- 4 atoms of carbon
- 8 atoms of hydrogen
- 2 atoms of oxygen
Therefore, the compound's molecular formula :
Regards :)