an organic compound contains carbon and oxygen which have a molecular mass of about 290 analysis of the compound 50%carbon present in it show what will be the molecular formula compound a
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The empirical formula =C
4
O
3
Mass =(4×12)+(3×16)=96
Molecular mass =290
∴ n=
96
290
=3 (approx)
Molecular formula =n× Empirical formula
=3×C
4
O
3
=C
12
O
9
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Answer:
The empirical formula =C4O3
Mass =(4×12)+(3×16)=96
Molecular mass =290
∴ n=96290=3 (approx)
Molecular formula =n× Empirical formula
=3×C4O3
=C12O9
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