Question

An organic compound contains carbon hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67 % and O, 51.62%. the empirical formula of the compound would be
_______.
(A) CHO
(B) CH₄O
(C) CH₃O
(D) CH₂O

Answer 1

Answer:

the emparical formula of the compound is CHO that is the option A

Answer 2

Answer:

(C) CH₃O

Explanation:

1 ) C

% =  38.71

Atomic Mass = 12

Mole ratio = 38.71/12 = 3.22

Simple Ratio =  3.22/3.22 = 1

2 ) H

% =  9.67

Atomic Mass = 1

Mole ratio = 9.67/1 = 9.67

Simple Ratio =  9,67/3.22 = 3

3 ) O

% =  51.62

Atomic Mass = 16

Mole ratio = 51,62/16 = 3.22

Simple Ratio =  3.22/3.22 = 1

Therefore, the empirical formula of the compound is CH₃O.