Question

An organic compound contains carbon, hydrogen and oxygen, Its
elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula
of the compound would be :
(a) CH₃O (b) CH₂O
(c) CHO (d) CH₄O

Answer 1

Answer:

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Explanation:

(a) CH³O

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Answer 2

Answer:

The empirical formula is to be calculated as:

Element % Composition   Atomic Mass Mole Ratio    Simple Ratio

C 38.71                               12                    38.71 /12=3.22    3.22/3.22=1

H 9.67                                 1                      9.67/1=9.67        9.67/3.22=3

O 100-(38.71+9.67) =51.6216                   51.62/16=3.22    3.22/3.22=1

Hence the empirical formula of the compound is CH₃O