An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C = 40%
and H = 6.66%. The empirical formula of the compound would be
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A)Element:- Carbon(C)
%Composition:-40.00%
Atomic mass:- 12
Mole ratio:- (40/12)
Simple ratio:- (3.33/3.33)=1
B)Element:- Hydrogen(H)
%Composition:-6.66%
Atomic mass:- 1
Mole ratio:- (6.67/1)
Simple ratio:- (6.667/3.33)=2
C)Element:- Oxygen(O)
%Composition:-53.33%
Atomic mass:-16
Mole ratio:-(53.33/16)
Simple ratio:- (3.33/3.33)=1
∴ Formula of compound is =CH2O
hope it's helpful
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