An organic compound contains carbon, hydrogen, oxygen. its elemental analysis gave C,38.71% and H,9.67%.The empirical formula of the compound would be?
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C-38.71% -38.71/12 - 3.225833 -3.225833/3.21375 -1
H-9.67%-9.67/1 - 9.67/3.21375-3
O-100-(38.71+9.67) =51.42-51.42%-51.42/16-3.21375/3.21375 -1
So empirical formula is CH3O. in first step divide %by 1 molar atom of element and then by smallest value among the three .Hope it helps you.... Mark me as Brainliest.
H-9.67%-9.67/1 - 9.67/3.21375-3
O-100-(38.71+9.67) =51.42-51.42%-51.42/16-3.21375/3.21375 -1
So empirical formula is CH3O. in first step divide %by 1 molar atom of element and then by smallest value among the three .Hope it helps you.... Mark me as Brainliest.
ayesha1999:
tysm
Good answer ! Thanks !!
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hope this helps you☺️☺️
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