Question

An organic compound cotain48% carbon, 8% hydrogen ,28%nitrogen,16%oxygen.write it's empirical formula​

Answer 1

Atomic mass :-

C - 12

H - 1

N - 14

O - 16

% ( Atomic mass)

C - 48 / 12 = 4

H - 8 / 1 = 8

N - 28 / 14 = 2

O - 16 / 16 = 1

Simplest ratio

C - 4/1 = 4

H - 8/1 = 8

N - 2/1 = 2

O - 1/1 = 1

Ratio :-

C - 4 , H - 8 , N - 2 , O - 1

Therefore,

Formula = C4H8N2O