An organic compound cotains 48% carbon,8%hydrogen,28%nitrogen,16%oxygen
write its empirical formula
Answers
Answered by
1
Answer:
48+8+28+16=100 %
=100%
Answered by
6
Explanation:
C=48%,H=8%,N=28%,O=16%
ATOMIC NUMBER MOLE
C=12 48÷12=4
H=1 8÷1=8
N =14 28÷14=2
O=16 16÷16=1
ATOMIC MASS RATIO SIMPLEST FORM(S.F)
C=4/1 4
H=8/1 8
N=2/1 2
O=1/1 1
SO,FROM S.F THE EMPIRICAL FORMULA IS
C4H8N2O1.
Similar questions