An organic compound crystallises in an orthorhombic
cell in the ratio of 2:1. The dimensions of cell are
12.05, 15.05 and 2.69 Å and density is 1.419 g/cm3.
Molar mass of the compound is-
@ 207g.mol-1
© 308g.mol-1
6 209g.mol-1
0 317g.mol-1
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Answer:
Density, ρ=a3×NAZ×M
Given,
Orthorhombic system has different edge length, width and height
∴a=12.05Ao=12.05×10−8 cm
b=15.05Ao=15.05×10−8 cm
c=2.69Ao=2.69×10−8 cm
∵ System has 2 molecules per unit cell,
∴Z=2
and NA=6.023×1023
Now, molecular mass will be
M=Zρ×a×b×c×NA
M=21.419×12.05×10−8×15.05×10−8×2.69×10−8×6.023×1023
M=2084.6×10−1=209 gmol−1.
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