Question

An organic compound had the following analyses C = 55.8%, H = 7.03% 0 - 372. ALS

sample was vaporized and was found to occupy 530 cm' at 100°C and 740 torr What is the molecular formula of the compound?​

Answer 1

Answer:

We have,

An organic compound C=57.8%

H=3.6%

Thus the oxygen is 38.6% Since the total %is100

So,

Molecular weight i=2×vapordensity

=2×83=166

So, Mass of C=\dfrac{57.8}{100}\times166$$

=95.948g

No pof carbon atoms =

12

95.948

=7.99∼8atoms Since

12=mass of the carbon

Mass of H=

100

3.6

×166=5.976∼6 atoms

Mass of O=

100

38.6

×166=64.076g

No of atoms =

16

64.076

=4atoms

Thus. The formulaa will be C

8

H6 O

Explanation:

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