An organic compound has carbon 48% Hydrogen 8% and Nitrogen 28% and reset of oxygen .calculate it"s empirical formula
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Explanation:
Element % at. mass at. ratio SR
C 48 12 48÷12=4 4÷1=4
H 8 1 8÷3=2.33 2.33÷1=2.33
N 28 14 28÷14=2 2÷1=2
O 16 16 16÷16=1 1÷1=1
C=4, H=2.33(rounded off to 2), N=2, O=1.
Therefore,The EMPIRICAL FORMULA of the compound is C4H2N2O.
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