An organic compound has following percentage
composition ,C=48%,H=8%,N=28%,O=16%.calculate
empirical formula of compound.
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Answer:C4H8N2O
Explanation:
mole of C = 48/12 = 4
mole of H = 8/1 = 8
mole of N = 28/14 = 2
mole of O = 16/16 = 1
Therefore C4H8N2O
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