an organic compound has the following percentage composition: C= 48%, H= 28%, N= 28%. calculate the empirical formula of the compound.
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C2H14N..... EMPIRICAL FORMULA
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Answer : The empirical formula of a compound is,
Solution : Given,
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 48 g
Mass of H = 28 g
Mass of N = 28 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of N = 14 g/mole
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of N =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For N =
The ratio of C : H : N = 2 : 14 : 1
The mole ratio of the element is represented by subscripts in empirical formula.
The Empirical formula =
Therefore, the empirical formula of a compound is,
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