An Organic Compound of relative molecular mass 46 on analysis was found to contain 52.0% Carbon, 13.3% hydrogen and 34.7% Oxygen. Determine its; a Emperical formular b Molecular formular c Draw the possible strcture of the compound
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a) Emperical formula - C₂H₆O
b) Molecular formula - C₂H₅OH
c) Structure - H₃C-CH₂-OH
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