An organic compound on analysis gave C=48gm H=8gm and N=56gm volume of 1gm of the compound was found to be 200ml at STP what is the molecular formula of the compound please answer my question
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Molecular formulae is C4H8N4
reason :
48g C is 4 moles of C
8g H is 8 moles of H
56g of N is 4 moles of N
therefore on adding the total mass of this substances
48+8+56 , We get 112g.
If 1g is 200ml , then 112g is 22400 ml.
which is 22.4L and 1 mole.
therefore 112g of this substance is 1 mole.
hence it's molecular weight is 112g.
Now, it's empirical formula is CH2N ( by taking common ratio of moles).
and it's empirical mass is 12+2+14 = 28g.
M.M/E.M = M.F/E.F
112/28 = M.M/CH2N
4(CH2N) = M.M
M.M=C4H8N4
reason :
48g C is 4 moles of C
8g H is 8 moles of H
56g of N is 4 moles of N
therefore on adding the total mass of this substances
48+8+56 , We get 112g.
If 1g is 200ml , then 112g is 22400 ml.
which is 22.4L and 1 mole.
therefore 112g of this substance is 1 mole.
hence it's molecular weight is 112g.
Now, it's empirical formula is CH2N ( by taking common ratio of moles).
and it's empirical mass is 12+2+14 = 28g.
M.M/E.M = M.F/E.F
112/28 = M.M/CH2N
4(CH2N) = M.M
M.M=C4H8N4
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