Question

an organic compound on analysis gave the following data :C=57.82%,H=3.6%and 38.58% is oxygen. Find its empirical formula.

Answer 1

please take a look at the solution and if their is any quarry you can ask me

Answer 2

The empirical formula of the compound is C₄H₃O₂.

Given,

% of Carbon = 57.82 %

% of Hydrogen = 3.6 %

% of Oxygen = 38.58 %

To Find,

The empirical formula of the compound

Solution,

We need to first find out the moles of the combining atoms,

For that, the percentage would be divided by molar mass

The molar mass of Carbon = 12 g

The molar mass of Hydrogen = 1 g

The molar mass of Oxygen = 16 g

Moles of Carbon = $\frac{57.82}{12}$

Moles of Carbon = 4.81

Moles of Carbon = $\frac{3.6}{1}$

Moles of Carbon = 3.6

Moles of Carbon = $\frac{38.58}{16}$

Moles of Carbon = 2.41

C: H : O:: 4.81: 3.6: 2.41

Dividing throughout by 2.41 we get -

C: H: O:: 2: 1.5: 1

Multiplying throughout with 2 we get -

C: H: O:: 4: 3: 2

Thus, the empirical formula is - C₄H₃O₂

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