Question

An organic compound on analysis was found to contain 10.06% of c 0.84% h and 89.10% of cl what will be the empirical formula of the substance

Answer 1

C H Cl3 is your answer

because here C contain is 12 times of H

and H = 1 & C = 12

It means C & H present only one molecule where Cl is 106 times more than H

and Cl = 35.5 so 106/ 35.5 ~ 3

so Cl present 3 molecule

so... Your Answer is CHCl3