Question

an organic compound present in vinegar as 40% carbon 6.6 % nitrogen and 53.4 % oxygen find the empirical formula​

Answer 1

The %age of oxygen is: 100 - (6.67 + 40)

= 100 - 46.67 = 53.33

Now, take the ratio of the percentage of the composition and molar mass

Hydrogen ratio: 6.67/1 = 6.67

Carbon ratio: 40/12 = 3.33

Oxygen ratio: 53.33/16  = 3.33

now, taking ratio: 3.33 : 6.67 : 3.33

= 1 : 2 : 1

So, empirical formula is: CH₂O

mass of empirical formula = 30

Molar mass of the compound is 60

Now, divide 60 by empirical formula mass = 60/30 = 2

n=2

Now, the formula is: C₂H₄O = CH₃CHO

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