Question

An organic compound was found to contain 3.045% carbon , 0.254% hydrogen and 96.70% iodine. its vapour density is 197. Find out its empirical and molecular formula
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Answer 1

Answer:

given :-

C = 3.045 %

H = 0.254 %

I = 96.70 %

01. 02. 03. 04. 05.

Element %comp At.mass 02/03 04/least value

C 3.045 12 3.045/12 0.25/0.76=0.32

H 0.254 1 0.254/1 0.254/0.76=0.33

I 96.70 126 96.70/126 0.76/0.76= 1

Now , Empirical formula = CHI

Molecular mass = 2 * vapour density

= 2*197

= 394

Empirical formula mass = (12*1) + (1*1) + (126*1)

= 12+1+126

= 139

n = molecular mass = 394 = 2.83

formula mass 139

Molecular mass = (Formula)n

= (CHI)3

= C3H3I3

Hope this ans help you !