Question

An organic compound was found to contain c=40.00%,h=8.47%and n=23.73%.Its vapour density was found to be 29.5 find its emperical and molecular formula

Answer 1

Answer:

Answer : The molecular of the compound is,

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.65 g

Mass of H = 8.55 g

Mass of N = 23.77 g

Mass of O = 100 - 72.97 = 27.03 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Moles of N =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

For N =

For O =

The ratio of C : H : N : O = 2 : 5 : 1 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula =

The empirical formula weight = 12(2) + 5(1) + 1(14) + 1(16) = 59 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

Molecular formula =

Therefore, the molecular of the compound is, C2H5NO

plz mark it brainlist