Question

An organic compound X(C4H9Br) on treatment with alc. KOH gave isomeric product with the formula C4H3. On ozonolysis
one of these gave only product CH3CHO while the other gave two different products. The compound X
Select one:
a. 1, 2 Dibromo butane
b. 2 - Bromobutane
C. 2 - Bromopentane
d. 3 - Bromopentene​

Answer 1

Answer:

answer is b

Explanation:

when when 2 bromo butane is reacted the product will be 2 butene if you further react with ozonolysis then there will be formation of acetaldehyde

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Answer 2

Answer:

b. 2 - Bromobutane

Explanation:

whilst 2 bromo butane is reacted the product can be 2 butene in case you similarly react with ozonolysis then there can be formation of acetaldehyde .Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to present compound (b). Compound (b) is reacted with HBr to present (c) that's an isomer of (a). When (a) is reacted with sodium metallic it offers compound (d), C8H18 which isn't the same as the compound shaped whilst n-butyl bromide is reacted with sodium. Give the structural components of (a) and write the equations for all of the reactions. primary-alkyl-halide-c4h9br-a-reacted-with-alcoholic-koh-to-give-compound-b.

So, the final answer is b. 2 - Bromobutane.

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