An organic compound 'X' having molecular formula C4H8O gives orange-red ppt. with 2, 4-DNP reagent. It does not reduce tollens' reagent but gives yellow ppt. of iodoform on heating with NaOI. Compound X on reduction with LiAIH4 gives compound 'Y' which undergoes dehydration reaction on heating with conc. H2SO4 to form But-2-ene. Identify the compounds X and Y.
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● Answers -
Compound X => Butan-2-one
Compound Y => Butan-2-ol
● Explanation -
Molecular formula C4H8O indicates X being either aldehyde or ketone.
As X doesn't reduce Tollen's reagent, it must be a ketone.
Postive iodoform test indicates methyl group at one end of ketone X.
Then compound X must be CH3-CO-C2H5 i.e. butan-2-one.
Butan-2-one (X) on reduction with LiAlH4 gives butan-2-ol (Y).
CH3-CO-C2H5 ---> CH3-CH(OH)-C2H5
Butan-2-ol (Y) on hydrolysis with conc.H2SO4 gives but-2-ene.
CH3-CH(OH)-C2H5 ---> CH3-CH=CH-CH3
Hope this helps you...
● Answers -
Compound X => Butan-2-one
Compound Y => Butan-2-ol
● Explanation -
Molecular formula C4H8O indicates X being either aldehyde or ketone.
As X doesn't reduce Tollen's reagent, it must be a ketone.
Postive iodoform test indicates methyl group at one end of ketone X.
Then compound X must be CH3-CO-C2H5 i.e. butan-2-one.
Butan-2-one (X) on reduction with LiAlH4 gives butan-2-ol (Y).
CH3-CO-C2H5 ---> CH3-CH(OH)-C2H5
Butan-2-ol (Y) on hydrolysis with conc.H2SO4 gives but-2-ene.
CH3-CH(OH)-C2H5 ---> CH3-CH=CH-CH3
Hope this helps you...
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