Question

An organic compound x (molecular formula c6h7o2n) has six carbon atoms in a ring system , two doible bomds and a nitro group as substituent , x is

Answer 1

it is homocyclic ( as the ring system is made up of one type of atomic i .e. carbon) .it is not aromatic .

Explanation:

as it does not have (4n+2)pi electron required for aromaticity

Answer 2

$\boxed{\boxed{\huge{\mathfrak{\red{Correct Question}}}}}$

An organic compound X(molecular formula C6H7O2N) has six carbon atoms in a ring system , two double bonds and a nitro group as substituent , X is

$\boxed{\boxed{\huge{\mathfrak{\blue{Answer}}}}}$

The compound is Homocyclic but not aromatic

$\large{\red{\underline{\underline{\tt{Explanation}}}}}$

It is Homocyclic as the ring has only carbon bonds & nitrogen is attached to carbon from outside.

For a compound to be aromatic, it must have (4n+2)π electrons.

Here two double bonds are present, 4π electrons are present in the compound.

Therefore, it is anti-aromatic.

${\bold{\blue{\text{Hope It Helps}}}}$