An organic compound X with a molecular formula C2H6O undergoes oxidation with in presence of alkaline KMnO4 to form a compound Y. X on heating in presence of Conc. H2SO4 at 443K gives Z. Which on reaction with H2O in the presence H2SO4 gives back `X` `Z` reacts with Br2 (aq) and decolorizes it. Identify X, Y, & Z and write the reactions involved.
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Compound x = ethanol
compound z = ethene
compound y = ethanoic acid
hope this help y
compound z = ethene
compound y = ethanoic acid
hope this help y
Answered by
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X - Ethanol
Y - Ethanoic acid
Z - ethene
C2H5OH ---> CH3COOH (presence of alkaline potassium permanganate)
C2H5OH ---> C2H4 + H2O (heated in the presence of Concentrated sulphuric acid at 443 K
C2H4 + Br2 ---> C2H4Br2
Ethene decolorises Bromine water because it is an unsaturated hydrocarbon.
Hope this helps you
Y - Ethanoic acid
Z - ethene
C2H5OH ---> CH3COOH (presence of alkaline potassium permanganate)
C2H5OH ---> C2H4 + H2O (heated in the presence of Concentrated sulphuric acid at 443 K
C2H4 + Br2 ---> C2H4Br2
Ethene decolorises Bromine water because it is an unsaturated hydrocarbon.
Hope this helps you
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