An organic compound X with a molecular formula C2H6O undergoes oxidation with in presence of alkaline KMnO4 to form a compound Y. X on heating in presence of Conc. H2SO4 at 443K gives Z. Which on reaction with H2O in the presence H2SO4 gives back `X` `Z` reacts with Br2 (aq) and decolorizes it. Identify X, Y, & Z and write the reactions involved.
Answers
Answered by
0
part-1C2H5OH+(O)
Alk-KMnO4
CH3CHO+H2O
C2H5OH
H2SO4-443°c
CH2=CH2+H2O
CH2=CH2+H2O→C2H5OH
Z X
CH2=CH2+Br2→CH2-CH2
Br....Br
colourless
part-2CH3COOH+C2H5OH→CH3COOC2H5+H2O
Acetic acid (A)Ethyl Acetate Ester(B)
CH3COOC2H5+H2O
H+
CH3COOH+C2H5OH
2CH3COOH+Na2CO3→2CH3COONa+CO2+H2O
Alk-KMnO4
CH3CHO+H2O
C2H5OH
H2SO4-443°c
CH2=CH2+H2O
CH2=CH2+H2O→C2H5OH
Z X
CH2=CH2+Br2→CH2-CH2
Br....Br
colourless
part-2CH3COOH+C2H5OH→CH3COOC2H5+H2O
Acetic acid (A)Ethyl Acetate Ester(B)
CH3COOC2H5+H2O
H+
CH3COOH+C2H5OH
2CH3COOH+Na2CO3→2CH3COONa+CO2+H2O
Similar questions