Question

an organic compounds has 68.327% c, 6 .406 h, 25. 267% cl . calculate the molecular formula of the compound of vapour density is

plz solve as fast as can​

Answer 1

Answer:

The empirical formula is CH2O. Therefore, the empirical weight = 30 g.

Given, the molecular weight = 2×V.D = 2×45=90 g.

x=Empirical weightMolecular weight=3090=3

Molecular Formula=(Empirical Formula)x

∴Molecular Formula=(CH2O)3=C3H6O3

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Answer 2

Answer:

ANSWER

The empirical formula is CH

2

O. Therefore, the empirical weight = 30 g.

Given, the molecular weight = 2×V.D = 2×45=90 g.

x=

Empirical weight

Molecular weight

=

30

90

=3

Molecular Formula=(Empirical Formula)

x

∴Molecular Formula=(CH

2

O)

3

=C

3

H

6

O

3