Question

An organo meyallic compound on analysis was found to contain c=64.4% , h=5.5% and fe=29.9%. Determine its empirical formula. (At mass of fe = 564)

Answer 1

Explanation:

Divide the respective percentages by their molecular weight

Carbon =>64.4%=>64.4/12 =>5.3667.

Hydrogen =>5.5% =>5.5/1 =>5.5

Iron(Fe) =>29.9%=>29.9/56.4 =>0.53

Now divide it by the smallest integer amongst them then

Carbon => 5.3667/0.53 => 10 approximately

Hydrogen =>5.5/0.53 => 10 approximately

Iron =>0.53/0.53 => 1

So the empirical formula of this compound is C10H10Fe. Hope it helps you.