Question

An ornament made of gold and copper which weight 57 gram if 3by19 of it is copper find the weight of pure gold in it

Answer 1

Answer:

An ornament made of gold and copper whose weight is 57 grams. If 3/19 of it is copper, then the weight of pure gold in it is 48grams.

Step-by-step explanation:

Given: Ornament weight = 57g, Ratio of copper by weight = 3 / 19

To Find: Weight of pure gold in the ornament.

Solution:

1. The ratio of copper by weight = 3/19, So, the ratio of pure gold by weight will be 1 - (3/19) which is equal to 16/19.
2. Now, we can obtain the weight of pure gold by simply multiplying the total weight of the ornament with the ratio of pure gold by the weight of the ornament.   $gold = weight * ratioofgold$

                                          $= 57 * \frac{16}{19}\\=48grams$