Question

An ornament of gold and silver weighing 12 kg is worth Rs. 24000, and if the weights of the two metals are interchanged the price of the ornament would be reduced by Rs. 4800 if the cost of gold is Rs. 2400 per kg, calculate the weight of silver in the ornament?
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Answer 1

Answer:

A lump of gold and silver weighing 240 gram worth rs 2640but if the gold and sliver weight is interchanged it would be worth rs 1800

Answer 2

Answer:

The weight of silver in the ornament is 8 kg.

Step-by-step explanation:

Given,an ornament of gold and silver weighing 12 kg is worth Rs. 24000

Let weight of gold be x kg and weight of silver be (12-x) kg.

Again given that cost of 1 kg gold is Rs. 2400 Let Cost of 1 kg silver be Rs.y

By Unitary method,

Cost of 1 kg gold is 2400 rupees.

So cost of x kg gold is

$(2400 \times x) = 2400x \: rupees$

and cost of 1 kg silver is y rupees

So cost of (12-x) kg silver is

$y \times (12 - x) \: rupees$

According to question,

$2400x + y(12 - x) = 24000 \\ 2400x + 12y - yx = 24000.....(1)$

Again given that weights of the two metals are interchanged the price of the ornament would be reduced by Rs. 4800.

So,now weight of gold is (12-x) rupees and weight of silver is x kg.

According to question,

$2400(12 - x) + yx = 24000 - 4800\\ 28800 - 2400x + yx = 19200....(2)$

We are adding equation (2) from equation (1),

$2400x + 12y - yx + (28800 + yx - 2400x) = 24000 + 19200$

$2400x + 12y - yx + 28800 + yx - 2400x= 24000 + 19200$

$12y + 28800 = 24000 + 19200 \\ 12y = 24000 + 19200 - 28800 \\ 12y = 14400 \\ y = \frac{14400}{12} \\ y = 1200$

So, price of 1 kg silver is 1200 rupees.

From equation (1),

2400x+1200(12-x)=24000

2400x+14400-1200x=24000

1200x=24000-14400

1200x=9600

x=9600/1200

x=8

So, weight of the silver in the ornaments is 8 kg.

Here we applied Unitary method.

Know more about Unitary method,

1) https://brainly.in/question/861311

2) https://brainly.in/question/861580